Part III Practice Problems on
Inferential Statistics
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Updated 3/27/18
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8) | The marketing director of the We'll Be Famous Company wants to determine
if age has an effect on target market acceptance of Quick Grow Finger Nail Paste. Using the 5-step approach to hypothesis testing, analyze this data at the .05 level of significance. Categorizing problems will help if you do not know what test to run. | ||||||
Customer Attitude Toward Quick Grow Finger Nail Paste | |||||||
Would Buy | Won't Buy |
Totals | |||||
Age | |||||||
Under 20 |
45 | 15 | 60 | ||||
20 and Over | 10 | 30 | 40 |
Part II Instructions: Use two paragraphs consisting of complete sentences to define an hypothesis test related to your major.
Part III Instructions: Use at least three paragraphs consisting of complete sentences to explain a business activity of a company you are familiar with, to describe the duties of a position at this company that would be of interest to you, and to define how this company could use the 5-step approach to hypothesis testing to solve a company problem. The wording of this question is specifically designed to give wide flexibility and freedom when writing your essay.
Please
1) z of 1.75 from the data is not beyond z critical of 1.96 for the .05 level of significance (divide by 2),
accept the null hypothesis, accounts receivables could equal the $375 stated on
the balance sheet.
2) 1) z of 1.75 from the data is beyond z critical of 1.645 from the .05 level of significance,
reject the null hypothesis, average accounts receivables could be larger than the $375 stated
on the balance sheet.
3) t of 1.75 from the data is not beyond t critical of 2.064 from the .05 level of significance
(divided by 2), accept
the null hypothesis, accounts receivables could equal the $375 stated on
the balance sheet.
4) t of 1.75 from the data is beyond t critical of 1.711 from the .05 level of significance, reject
the null hypothesis, average accounts receivables could be larger than the $375 stated
on the balance sheet.
5) t of -2.69 from the data is not beyond t critical of -2.977 from the .01 level of significance
(divided by two), accept the null hypothesis, the time it takes to make parts does not differ for the two shifts.
6) t of -5.08 from the data is beyond t critical of -2.132 from
the .05 level of significance, reject the null hypothesis,
scores improved.
7) 5.0 < 13.28, accept the null hypothesis at the .01 level of significance, absences happen equally throughout the week.
8) 24.24 > 3.84, reject the null hypothesis at the .05 level of significance. There is a
relationship and customer acceptance is dependent upon age.
Consider
Quick Statistics Using Microsoft
(TM) Excel
for the fastest and easiest way to do these and other
statistical tests.